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22x^2+127x-33=0
a = 22; b = 127; c = -33;
Δ = b2-4ac
Δ = 1272-4·22·(-33)
Δ = 19033
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(127)-\sqrt{19033}}{2*22}=\frac{-127-\sqrt{19033}}{44} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(127)+\sqrt{19033}}{2*22}=\frac{-127+\sqrt{19033}}{44} $
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